Ask Question
13 August, 19:52

A basketball player throws a chall - 1 kg up with an initial speed of his hand at shoulder height = 2.15 m Le gravitational potential energy ber ground level the ball leves 50%. (a) Give the total mechanical energy of the ball E in terms of maximum height Am it reaches, the mass m, and the gravitational acceleration g. (b) What is the height, hm in meters?

+3
Answers (1)
  1. 13 August, 20:04
    0
    Complete Question:

    A basketball player tosses a basketball m=1kg straight up with an initial speed of v=7.5 m/s. He releases the ball at shoulder height h = 2.15m. Let gravitational potential energy be zero at ground level

    a) Give the total mechanical energy of the ball E in terms of maximum height hn it reaches, the mass m, and the gravitational acceleration g.

    b) What is the height, hn in meters?

    Answer:

    a) Energy = mghₙ

    b) Height, hₙ = 5.02 m

    Explanation:

    a) Total energy in terms of maximum height

    Let maximum height be hₙ

    At maximum height, velocity, V=0

    Total mechanical energy, E = mgh + 1/2 mV^2

    Since V=0 at maximum height, the total energy in terms of maximum height becomes

    Energy = mghₙ

    b) Height, hₙ in meters

    mghₙ = mgh + 1/2 mV^2

    mghₙ = m (gh + 1/2 V^2)

    Divide both sides by mg

    hₙ = h + 0.5 (V^2) / g

    h = 2.15m

    g = 9.8 m/s^2

    V = 7.5 m/s

    hₙ = 2.15 + 0.5 (7.5^2) / 9.8

    hₙ = 2.15 + 2.87

    hₙ = 5.02 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A basketball player throws a chall - 1 kg up with an initial speed of his hand at shoulder height = 2.15 m Le gravitational potential ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers