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11 February, 20:13

n a car lift used in a service station, compressed air exerts a force on a small piston that has a circular cross section of radius 5.00 cm. This pressure is transmitted by a liquid to a piston that has a radius of 15.0 cma) What force must the compressed air exert to lift a car weighing 13300 N

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  1. 11 February, 20:23
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    Answer: 1477.78 N

    Explanation:

    Let's assume that the cross sectional area of the smaller piston be A1

    let's also assume the cross sectional area of the larger piston be A2

    We assume the force applied to the smaller piston be F1

    We also assume the force applied to the larger piston be F2

    we then use the formula

    F1/A1 = F2/A2

    From our question,

    The radius of the smaller piston is 5 cm = 0.05 m

    The radius of the larger piston is 15 cm = 0.15 m

    The force of the larger piston is 13300 N

    The force of the smaller piston is unknown = F

    A1 = πr² = 3.142 * 0.05² = 0.007855 m²

    A2 = πr² = 3.142 * 0.15² = 0.070695 m²

    F1/0.007855 = 13300/0.070695

    F1 = (13300 * 0.007855) / 0.070695

    F1 = 104.4715 / 0.070695

    F1 = 1477.78 N

    Thus, the force the compressed air must exert is 1477.78 N
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