A test charge is placed at a distance of 3.5 meters from a charge of 8.7 x 109 coulombs. What is the electric field strength at the test charge? (k 9.0 x 109 newton-meter2/coulomb)

Question

Zachariah Miranda

Physics

6 January, 03:27

A test charge is placed at a distance of 3.5 meters from a charge of 8.7 x 109 coulombs. What is the electric field strength at the test charge? (k 9.0 x 109 newton-meter2/coulomb)

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Bradford · Answer 1

In order to calculate the electric field strength, we may use the formula:E = kQ/d²Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:E = (9 x 10⁹) (8.7 x 10⁻⁹) / (3.5²) E = 6.39 Newtons per coulombTherefore, the answer is 6.4 Newtons/coulomb