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22 July, 20:07

a ball is rolled down hill with an initial velocity of 4.2 m/s. how far will it roll in 11.6s if it accelerates at 2.3m/s2

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  1. 22 July, 20:19
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    Given:

    x₀ = 0 m

    v₀ = 4.2 m/s

    t = 11.6 s

    a = 2.3 m/s²

    Find: x

    x = x₀ + v₀ t + ½ at²

    x = 0 m + (4.2 m/s) (11.6 s) + ½ (2.3 m/s²) (11.6 s) ²

    x ≈ 203 m

    Round as needed.
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