As a new electrical technician, you are designing a large solenoid to produce a uniform 0.160 {/rm T} magnetic field near the center of the solenoid. You have enough wire for 4200 circular turns. This solenoid must have a length of 1.25 {/rm m} and a diameter of 19.0 {/rm cm}. What current will you need to produce the necessary field?

Question

Arthur

Physics

10 January, 14:15

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.160 {/rm T} magnetic field near the center of the solenoid. You have enough wire for 4200 circular turns. This solenoid must have a length of 1.25 {/rm m} and a diameter of 19.0 {/rm cm}. What current will you need to produce the necessary field?

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Answers (1)

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Joey Stone · Answer 1

Answer: I = 0.00383A (approx.)

Explanation:

Using the formula:

B = uni

Where B = magnetic field; 0.160mT

= 0.160 * 10^-2 m/T

n = N/L; N = 4200 turns,

L = 1.25mm = 1.25 * 10^-3m

u = 4π * 10 ^ - 7.

Now since magnetic field inside a solenoid is independent of dimension B = uNI/L

I = BL/uN

= 0.00162 * 0.00125 / (4200 * 4π * 10 ^ - 7)

I = 0.00384A