Ask Question
18 November, 05:43

A child sitting 1.90 m from the center of a merry-go-round moves with a speed of 2.05 m/s. Calculate the centripetal acceleration of the child. Calculate the net horizontal force exerted on the child. (mass = 28.5 kg).

+5
Answers (1)
  1. 18 November, 05:58
    0
    Acceleration = 2.21m/s^2

    Force = 62.99N

    Explanation:

    Centripetal acceleration = v^2 / r

    Given velocity v = 2.05m/s

    Radius r = 1.90m

    Centripetal acceleration = (2.05) ^2 / 1.90

    2.05 x 2.05 / 1.90

    4.2025/1.90

    2.21m/s^2

    Now, since a = 2.21 m/s^2

    And mass m = 28.5kg

    Force exerted on the child = mass x centripetal acceleration

    That's 28.5kg x 2.21m/s^2

    62.99N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A child sitting 1.90 m from the center of a merry-go-round moves with a speed of 2.05 m/s. Calculate the centripetal acceleration of the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers