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22 April, 18:59

A flashlight bulb operating at a voltage of 14.4 V has a resistance of 11.0 Ω. How many electrons pass through the bulb filament per second (e = 1.6 ' 10-19 C) ? (Give your answer to two significant figures)

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  1. 22 April, 19:23
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    For a DC circuit, the following equation relates the voltage, resistance, and current:

    V = IR

    V is the total voltage supplied, I is the total current, and R is the total resistance.

    Given values:

    V = 14.4V

    R = 11.0Ω

    Plug in the values and solve for I:

    14.4 = I*11.0

    I = 1.309A

    Since one electron carries 1.6*10⁻¹⁹C of charge, divide the current by this number.

    1.309 / (1.6*10⁻¹⁹) = 8.182*10¹⁸

    Round this value to 2 significant figures:

    8.2*10¹⁸ electrons per second.
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