Two hockey players are traveling at velocities of v1 = 10 m/s and v2 = - 22 m/s when they undergo a head-on collision. after the collision, they grab each other and slide away together with a velocity of - 3.6 m/s. hockey player 1 has a mass of 123 kg. what is the mass of the other player?

Question

Jayla Bryant

Physics

20 November, 23:24

Two hockey players are traveling at velocities of v1 = 10 m/s and v2 = - 22 m/s when they undergo a head-on collision. after the collision, they grab each other and slide away together with a velocity of - 3.6 m/s. hockey player 1 has a mass of 123 kg. what is the mass of the other player?

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Ulises Rocha · Answer 1

The negative sign in the velocity simply indicate direction, nothing else. From the conservation of momentum, we have the equation:

m1 v1 + m2 v2 = (m1 + m2) v’

123 kg (10 m/s) + m2 (-22 m/s) = (123 kg + m2) (-3.6 m/s)

1230 - 22 m2 = - 442.8 - 3.6 m2

18.4 m2 = 1672.8

m2 = 90.91 kg