The drawing shows a type of flow meter that can be used to measure the speed of blood in situations when a blood vessel is sufficiently exposed (e. g., during surgery). Blood is conductive enough that it can be treated as a moving conductor. When it flows perpendicularly with respect to a magnetic field, as in the drawing, electrodes can be used to measure the small voltage that develops across the vessel. Suppose the speed of the blood is 0.19 m/s and the diameter of the vessel is 4.7 mm. In a 0.52-T magnetic field what is the magnitude of the voltage that is measured with the electrodes in the drawing?

Question

Anahi Keller

Physics

10 April, 05:06

The drawing shows a type of flow meter that can be used to measure the speed of blood in situations when a blood vessel is sufficiently exposed (e. g., during surgery). Blood is conductive enough that it can be treated as a moving conductor. When it flows perpendicularly with respect to a magnetic field, as in the drawing, electrodes can be used to measure the small voltage that develops across the vessel. Suppose the speed of the blood is 0.19 m/s and the diameter of the vessel is 4.7 mm. In a 0.52-T magnetic field what is the magnitude of the voltage that is measured with the electrodes in the drawing?

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Answers (1)

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Lili · Answer 1

4.64 * 10^-3V

Explanation:

4. The blood flowing at a speed v = speed of the moving rod

While the diameter of the blood vessel = length of the rod.

Let:

The magnitude of the magnetic field = B = 0.52-T

emf = the measured voltage = ?

Length, L = 4.7mm = 4.7 * 10^-3m

Speed of the blood, V = 0.19m/s

Recall:

emf = B V L

= (0.52) (0.19) (4.7 * 10^-3)

=0.000464

= 4.64 * 10^-3V