An object is thrown upward with a speed of 14 m/s on the surface of planet X where the acceleration due to gravity is 3.5 m/s2. How long, in seconds, does it take for the object to reach the maximum height?

Question

Sawyer Woods

Physics

10 February, 01:19

An object is thrown upward with a speed of 14 m/s on the surface of planet X where the acceleration due to gravity is 3.5 m/s2. How long, in seconds, does it take for the object to reach the maximum height?

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Answers (2)

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Siena Meyers · Answer 1

The maximum height of the object is where the final velocity becomes zero. The final velocity is obtained by,

Vf = V1 - gt

Substituting the known values,

0 = 14 m/s - (3.5 m/s²) t

The value of t is 4 seconds.

Killian Mcneil · Answer 2

U = 14 m/s, g = 3.5 m/s². At maximum height, v = 0

v = u - gt

0 = 14 - 3.5t

3.5t = 14

t = 14/3.5

t = 4

time = 4 seconds