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11 June, 16:15

A 30.0-kg girl in a swing is pushed to one side and held at rest by a horizontal force / vec{F} F ⃗ so that the swing ropes are 30.0^/circ30.0 ∘ with respect to the vertical. Calculate the tension in each of the two ropes supporting the swing under these conditions.

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  1. 11 June, 18:13
    0
    169.74 N

    Explanation:

    Given,

    Mass of the girl = 30 Kg

    angle of the rope with vertical, θ = 30°

    equating the vertical component of the tension

    vertical component of the tension is equal to the weight of the girl.

    T cos θ = m g

    T cos 30° = 30 x 9.8

    T = 339.48 N

    Tension on the two ropes is equal to 339.48 N

    Tension in each of the rope = T/2

    = 339.48/2 = 169.74 N

    Hence, the tension in each of the rope is equal to 169.74 N
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