The magnetic field strength within a long solenoid isb=4.0t t, where t is time in seconds. if the radius of thesolenoid is1.0 cm, what is the magnitude of the non-coulomb force that acts on a6.0 c charge a distance6.0 cmfrom the axis of the solenoid?

Question

Paul Cooke

Physics

22 February, 08:01

The magnetic field strength within a long solenoid isb=4.0t t, where t is time in seconds. if the radius of thesolenoid is1.0 cm, what is the magnitude of the non-coulomb force that acts on a6.0 c charge a distance6.0 cmfrom the axis of the solenoid?

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Answers (1)

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Jerome Simmons · Answer 1

The current problem can solved by using Faraday's law of induction which is actually one of the Maxwell's equations. It is stated as follows:

F=qE

Where

F = Non-coulomb force

q = 6.0 C

E = (dB/dt) * r^2 * (2/R); In which dB/dt = 4 T; r = 1 cm = 0.01 m, R = 6.0 cm = 0.06 m, E = Newtons/Coulob

Substituting;

E = 4*0.01^2 * (2/0.06) = 1/75

Therefore,

F = qE = 6*1/75 = 0.08 N