Ask Question
7 October, 20:23

In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s. As he moves through his linemen, he accelerates at a rate of 1.71 yards/s^2 to a velocity of 7.54 yards/s before he is tackled. How far did he run after he got the ball?

+2
Answers (1)
  1. 7 October, 20:31
    0
    Given Information:

    Initial speed = u = 3.21 yards/s

    Acceleration = α = 1.71 yards/s²

    Final speed = v = 7.54 yards/s

    Required Information:

    Distance = s = ?

    Answer:

    Distance = s = 13.61

    Explanation:

    We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.

    We know from the equations of motion,

    v² = u² + 2αs

    Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.

    Re-arranging the above equation for distance yields,

    2αs = v² - u²

    s = (v² - u²) / 2α

    s = (7.54² - 3.21²) / 2*1.71

    s = 46.55/3.42

    s = 13.61 yards

    Therefore, the runner traveled a distance of 13.61 yards before being tackled.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s. As he moves through his linemen, ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers