Ask Question
26 October, 05:42

A catapult used by medieval armies hurls a stone of mass 32.0 kg with a velocity of 50.0 m/s at a 30.0 degree angle above the horizontal. What is the horizontal distance traveled when the stone returns to its original height? Ignore air resistance. Check your calculator deg/rad mode.

+3
Answers (1)
  1. 26 October, 05:45
    0
    The horizontal distance traveled when the stone returns to its original height = 220.81 m

    Explanation:

    Considering vertical motion of catapult:-

    At maximum height,

    Initial velocity, u = 50 sin30 = 25 m/s

    Acceleration, a = - 9.81 m/s²

    Final velocity, v = 0 m/s

    We have equation of motion v = u + at

    Substituting

    v = u + at

    0 = 25 - 9.81 x t

    t = 2.55 s

    Time of flight = 2 x Time to reach maximum height = 2 x 2.55 = 3.1 s

    Considering horizontal motion of catapult:-

    Initial velocity, u = 50 cos30 = 43.30 m/s

    Acceleration, a = 0 m/s²

    Time, t = 5.10 s

    We have equation of motion s = ut + 0.5 at²

    Substituting

    s = ut + 0.5 at²

    s = 43.30 x 5.10 + 0.5 x 0 x 5.10²

    s = 220.81 m

    The horizontal distance traveled when the stone returns to its original height = 220.81 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A catapult used by medieval armies hurls a stone of mass 32.0 kg with a velocity of 50.0 m/s at a 30.0 degree angle above the horizontal. ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers