1 November, 03:06

# An object with a momentum of 1500 kg-m/s directed east is acted upon by an impulse of 100.0 kg-m/s in the same direction. What is the final momentum of the object? 14. A 100 kg ball is initially traveling at 10 m/s. If the ball experiences a constant external force that increases the ball's velocity to 15 m/s, what is the net impulse that acted on the ball?

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1. 1 November, 03:18
0
The final momentum of the body = 1600 kgm/s

Thus the impulse that acted on the body. = 500 N. s

Explanation:

Momentum: This can be defined as the product of mass and velocity. The S. I unit of momentum is kgm/s. Momentum is a vector quantity.

Mathematically, momentum can be expressed as

M = mv.

Where M = momentum of the object, m = mass of the object, v = velocity of the object.

Impulse acting on the object = Final momentum of the object - initial momentum of the object

I = M₂ - M₁

M₂ = I + M₁ ... Equation 1

Where I = impulse, M₁ and M₂ = Final and initial momentum.

Note:

(i) The momentum and impulse act in the same direction

(ii) impulse is also a vector quantity.

Given: M₁ = 1500 kgm/s, I = 100 kgm/s.

Substituting these values into equation 1

M₂ = 1500 + 100

M₂ = 1600 kgm/s.

Thus the final momentum of the body = 1600 kgm/s

14.

I = m (v-u) ... Equation 2.

Where I = impulse on the object, m = mass of the object, v = final velocity, u = initial velocity.

Given: m = 100 kg, v = 15 m/s, u = 10 m/s.

I = 100 (15-10)

I = 100 (5)

I = 500 N. s or 500 kgm/s.

Thus the impulse that acted on the body. = 500 N. s