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12 June, 00:00

If a golf ball is swinging on a pendulum on the planet mars (g=3.711 m/s²) and it takes 7 seconds to complete one oscillation, what is the approximate length of the pendulum?

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  1. 12 June, 00:10
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    T = 2*pi*Sqrt (L/g)

    T = Period = Time to complete one oscillation, L = Length of the pendulum, g = gravitational acceleration.

    Then,

    L = {T / (2*pi) }^2*g = {7 / (2*pi) }^2*3.711 = 4.606 m
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