2. Derive an expression for the final velocity of an object dropped from some height (h)

above the ground, initially at rest, the instant before hits the ground. Your equation

should be in terms of (h) and (g) only

Question

Wiz

Physics

7 February, 14:26

2. Derive an expression for the final velocity of an object dropped from some height (h)

above the ground, initially at rest, the instant before hits the ground. Your equation

should be in terms of (h) and (g) only

+4

Answers (1)

Know the Answer?

Lorenzo Frost · Answer 1

v = √ (2gh)

Explanation:

Given:

Δy = h

v₀ = 0

a = g

Find: v

v² = v₀² + 2aΔy

v² = (0) ² + 2gh

v = √ (2gh)

You can also prove this with conservation of energy.

PE = KE

mgh = ½mv²

v = √ (2gh)

2. Derive an expression for the final velocity of an object dropped from some height (h)above the ground, initially at rest, the instant before hits the ground. Your equationshould be in terms of (h) and (g) only

2. Derive an expression for the final velocity of an object dropped from some height (h)

above the ground, initially at rest, the instant before hits the ground. Your equation

should be in terms of (h) and (g) only