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7 February, 14:26

2. Derive an expression for the final velocity of an object dropped from some height (h)

above the ground, initially at rest, the instant before hits the ground. Your equation

should be in terms of (h) and (g) only

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Answers (1)
  1. 7 February, 14:39
    0
    v = √ (2gh)

    Explanation:

    Given:

    Δy = h

    v₀ = 0

    a = g

    Find: v

    v² = v₀² + 2aΔy

    v² = (0) ² + 2gh

    v = √ (2gh)

    You can also prove this with conservation of energy.

    PE = KE

    mgh = ½mv²

    v = √ (2gh)
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