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17 March, 23:54

If 51.9 C of charge are transferred in a specific lightning strike and the potential difference is ∆V = 10.93 MV, how much energy is released in this lightning strike? (in J

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  1. 17 March, 23:58
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    Quantity of charge unloaded = 51.9 Coulombs

    Potential difference = 10.93 megavolts = 1.093 x 10⁷ volts

    1 volt = 1 joule per coulomb

    1.093 x 10⁷ volts = 1.093 x 10⁷ joules per coulomb

    Energy = (1.093 x 10⁷ J/C) x (51.9 C)

    Energy = 567.267 megaJoules

    That's 5.67 x 10⁸ Joules.

    ==> My wife's blow-dryer is marked 1260 watts.

    If the energy in this lightning strike could be collected, bottled, stored, and used as needed, it could run my wife's blow-dryer for 125 hours. That would save us more than $30 on our electric bill!
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