Suppose the length of the year were 365.20 days instead of 365.25 days. How often would you have a leap year? Every

a. 2 years.

b. 5 years.

c. 10 years.

d. 20 years.

e. 50 years.

Question

Bonnie

Physics

25 February, 10:10

Suppose the length of the year were 365.20 days instead of 365.25 days. How often would you have a leap year? Every

a. 2 years.

b. 5 years.

c. 10 years.

d. 20 years.

e. 50 years.

+3

Answers (1)

Know the Answer?

Snickers · Answer 1

That day that is added every 4 years, is added to 'complete' the missing day figure. If 0.25 (1/4) is a quarter of 1:

"Leap year" equal to: 0.25 + 0.25 + 0.25 + 0.25 = 1

0.20 (1/5) would involve the 5 part of a day:

0.20 + 0.20 + 0.20 + 0.20 + 0.20 = 1

In other words, to complete that unit, it would be necessary to carry out a leap year every 5 years.

The correct answer is B.

Suppose the length of the year were 365.20 days instead of 365.25 days. How often would you have a leap year? Everya. 2 years.b. 5 years.c. 10 years.d. 20 years.e. 50 years.

Suppose the length of the year were 365.20 days instead of 365.25 days. How often would you have a leap year? Every

a. 2 years.

b. 5 years.

c. 10 years.

d. 20 years.

e. 50 years.