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22 October, 09:54

A 5.0 kg dog sits on the floor of an elevator that is accelerating downward at 1.20 m/s^2.?

A) What is the magnitude of the normal force of the elevator floor on the dog?

B) What is the magnitude of the force of the dog on the elevator floor?

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  1. 22 October, 10:01
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    A)

    Upward force = Normal Force

    Downward force = weight

    Resultant force = ma

    Resultant = Weight - Normal

    1.2 x 5 = 1.2 x 9.81 - Fn

    Fn = 5.77 N

    B)

    The reactant force is equal to the force exerted by the dog, just in the opposite direction. Thus, the dog's force is also 5.77 N.
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