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9 August, 19:31

A traveler pulls on a suitcase strap at an angle 36° above the horizontal. If 908 J of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap?

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  1. 9 August, 19:48
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    T = 74.8 N

    Explanation:

    Given:

    - The angle with the horizontal θ = 36°

    - The tension in the strap T

    - The amount of work done W = 908 J

    - The distance travelled by the suitcase s = 15 m

    Find:

    what is the tension in the strap?

    Solution:

    - From definition we have that the work-done by a force F is given by the dot product of the force vector and the displacement vector as expressed below:

    W = F. s

    - The scalar form of the work done includes the component of force F along the direction of displacement as follows:

    W = F*s*cos (θ)

    - Now we can calculate the Tension force T from the given data as follows:

    W = T*s*cos (θ)

    T = W / (s*cos (θ))

    T = 908 / (15*cos (36))

    T = 74.8 N
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