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24 February, 03:59

A vw beetle goes from 0 to 60 mi/h with an acceleration of 2.35 m/s^2.

a. how much time does ti take for the beetle to reach 60 mi/h?

b. a top - fuel dragster can go from 0 to 60 mi/h in 0.600 seconds. find the acceleration (m/s^2) of the dragster.

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  1. 24 February, 04:08
    0
    Part a.

    u = 0, the initial velocity

    v = 60 mi/h, the final velocity

    a = 2.35 m/s², the acceleration.

    Note that

    1 m = 1609.34 m.

    Therefore

    v = (60 mi/h) * (1609.34 m/mi) * (1/3600 h/s) = 26.822 m/s

    Use the formula

    v = u + at

    (26.822 m/s) = (2.35 m/s²) * (t s)

    t = 26.822/2.35 = 11.4 s

    Answer: 11.4 s

    Part b.

    We already determined that v = 60 mi/h = 26.822 m/s.

    t = 0.6 s

    Therefore

    (26.822 m/s) = (a m/s²) * (0.6 s)

    a = 26.822/0.6 = 44.7 m/s²

    Answer: 44.7 m/s²
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