Ask Question
23 March, 22:24

A one-piece cylinder has a core section protruding from the larger drum and is free to rotate around its central axis. A rope wrapped around the drum of radius 1.39 m exerts a force of 3.34 N to the right on the cylinder. A rope wrapped around the core of radius 0.48 m exerts a force of 8.52 N downward on the cylinder. What is the magnitude of the net torque acting on the cylinder about the rotation axis? Answer in units of N ∗ m.

+4
Answers (1)
  1. 23 March, 22:31
    0
    Torque created by force 3.34N

    = 3.34 x 1.39 = 4.64 N. m

    This torque is acting in clockwise direction.

    Torque created by force 8.52 N

    8.52 x. 48

    = 4.09 N. m

    The force of 8.52 N is acting downward. It may turn the cylinder in clockwise or anticlockwise direction. So we shall consider both the possibilities.

    If it rotates the cylinder in clockwise direction

    Total torque = 4.64 + 4.09

    = 8.73 Nm

    If it rotates the cylinder in anticlockwise direction

    Total torque = 4.64 - 4.09

    =.55 Nm

    Net torque will be in clockwise direction.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A one-piece cylinder has a core section protruding from the larger drum and is free to rotate around its central axis. A rope wrapped ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers