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11 January, 11:23

A 20-μF capacitor has a charge of 60 μC. How much energy is stored in this capacitor? A) 100 μJ B) 80 μJ C) 90 μJ D) 70 μJ E) 110 μJ

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  1. 11 January, 11:25
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    C ... 90

    Explanation:

    Energy stored = 1/2 of (Charge * Voltage)

    ... then substitute Voltage with (Charge : Capacitance)

    Then obtain the formula for energy stored as ...

    E = 1/2 of (Charge) ^2 : Capacitance

    = 0.5 x (60^2:20)

    ; Energy stored = 90
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