Ask Question
4 January, 14:15

1) A force of 20 Newton acts on a bar having a cross sectional area of 0.8m^2 and length 10cm. calculate the stress developed in the bar

+3
Answers (1)
  1. 4 January, 14:36
    0
    Answer:25N/M^2

    Explanation:

    Force=20N Area=0.8M^2

    Stress=force/area

    Stress=20/0.8

    Stress=25N/M^2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “1) A force of 20 Newton acts on a bar having a cross sectional area of 0.8m^2 and length 10cm. calculate the stress developed in the bar ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers