Ask Question
22 August, 05:49

Two charges 5 c and 15 c are seperated by 10 cm. what is the electric force between them?

+3
Answers (1)
  1. 22 August, 05:52
    0
    6.75*10^13N

    Explanation:

    The electric force between the charges can be determined using coulombs law which states that 'the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of their distance between them.

    Mathematically, F = kq1q2/r² where;

    q1 and q2 are the charges

    r is the distance between the charges

    F is the force of attraction

    k is the coulombs constant

    Given q1 = 5C q2 = 15C r = 10cm = 0.1m k = 9*10^9Nm²/C²

    Substituting the given values in the formula we have;

    F = 9*10^9*5*15/0.1²

    F = 6.75*10^11/0.01

    F = 6.75*10^13N

    Therefore the electric force between them is 6.75*10^13N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Two charges 5 c and 15 c are seperated by 10 cm. what is the electric force between them? ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers