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14 November, 19:35

The inner and outer surfaces of a 5m x 6m brick wall of thickness 30 cm and thermal conductivity 0.69 w/m. 0 c are maintained at temperature of 20 0 c and 50 c, respectively. determine the rate of heat transfer through the wall, in w.

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  1. 14 November, 20:01
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    The working equation to be used here is written below:

    Q = kA (T₁ - T₂) / Δx

    where

    Q is the rate of heat transfer

    k is the heat transfer coefficient

    A is the cross-sectional area of the wall

    T₁ - T₂ is the temperature difference between the sides of the wall

    Δx is the thickness of the wall

    The solution is as follows:

    Q = (0.69 W/m²·°C) (5 m * 6 m) (50°C - 20°C) / (30 cm * 1 m/100 cm)

    Q = 2,070 W/m
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