An electron is ejected horizontally at a speed of 1.5 ✕ 106 m/s from the electron gun of a computer monitor. if the viewing screen is 35 cm away from the end of the gun, how far will the electron travel in the vertical direction before hitting the screen?

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Freedom

Physics

17 December, 01:21

An electron is ejected horizontally at a speed of 1.5 ✕ 106 m/s from the electron gun of a computer monitor. if the viewing screen is 35 cm away from the end of the gun, how far will the electron travel in the vertical direction before hitting the screen?

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Bailey Williamson · Answer 1

GivenHorizontal velocity, vxi = 1.5 * 10^6 m/sDistance, x = 0.35 mFirst we will calculate the time takenx = vxi t0.35 m = (1.5 * 10^6 m/s) tt = 0.23 * 10^-6 sThe vertical distance travelled by the electron isy = 1/2 gt^2 = 0.5 * 9.8 m/s^2 * (0.23 * 10^-6 s) ^2 = 0.25 * 10^-12 m

Therefore, the answer is 0.25 * 10^-12 m