Ask Question
15 February, 02:26

During a very quick stop, a car decelerates at 7.00 m/s2. What is the angular acceleration of its 0.280-m-radius tires, assuming they do not slip on the pavement

+4
Answers (1)
  1. 15 February, 02:33
    0
    Answer: - 25 rad/s²

    Explanation: The linear acceleration (a) is related to angular acceleration (α) is given as

    a = αr

    -7.00 = α (0.280)

    α = - 7 / 0.280 = - 25 rad/s²

    The negative sign denotes deceleration
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “During a very quick stop, a car decelerates at 7.00 m/s2. What is the angular acceleration of its 0.280-m-radius tires, assuming they do ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers