A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.4°C Mass of water 0.403 kg Mass of calorimeter 0.04 kg Specific heat of calorimeter 0.62 kJ/kg·°C Initial temperature of aluminum 26.9°C Mass of aluminum 0.199 kg Final temperature of mixture 66.2°C (a) Use these data to determine the specific heat of aluminum. J/kg · °C (b) Is your result within 15% of 900 J/kg · °C?

Question

Misael Huff

Physics

31 May, 16:36

A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.4°C Mass of water 0.403 kg Mass of calorimeter 0.04 kg Specific heat of calorimeter 0.62 kJ/kg·°C Initial temperature of aluminum 26.9°C Mass of aluminum 0.199 kg Final temperature of mixture 66.2°C (a) Use these data to determine the specific heat of aluminum. J/kg · °C (b) Is your result within 15% of 900 J/kg · °C?

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Answers (1)

Know the Answer?

Keira Roman · Answer 1

Answer: a) Cal = 828 J/Kg °C b) yes

Explanation: Using the energy conservation, it means the heat absorbed by the piece of Aluminium from the heat coming from the calorimeter and the hot water

The balance equation is given by;

C water 4186 J/Kg °C