Zoe has 25 grams of water (c = 4.186) at 10°C, which she mixes with 12 grams of water at 30°C. Assume that no heat is lost to the surroundings. What is the final temperature of the two liquids? The answer is expressed to the nearest whole number.

Question

Ace Arellano

Physics

2 November, 17:40

Zoe has 25 grams of water (c = 4.186) at 10°C, which she mixes with 12 grams of water at 30°C. Assume that no heat is lost to the surroundings. What is the final temperature of the two liquids? The answer is expressed to the nearest whole number.

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Answers (2)

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Jordon Perkins · Answer 1

Since heat here is conserved that means that the heat out is equal to the heat in. We use the expression Q = mC (T2-T1). We caclulate as follows:

Q absorbed = Q released

m1 C (T-T1) = - m2 C (T-T1)

C can be cancelled since they are the same substance.

m1 (T-T1) = - m2 (T-T1)

25 (T-10) = - 12 (T-30)

T = 16.49 degrees Celsius

Hugo Quinn · Answer 2

T = 16.49 degrees Celsius