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11 August, 10:42

10 μF, and a 18 μF, and a capacitor are connected in series. How much capacitance would a single capacitor need to have to replace the three capacitors?

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  1. 11 August, 10:43
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    6.429 μ F

    Explanation:

    C1 = 10 μ F

    C2 = 18 μ F

    Let C be the equivalent capacitance of the circuit.

    They are connected in series combination

    1 / C = 1 / C1 + 1 / C2

    1 / C = 1 / 10 + 1 / 18

    1 / C = (18 + 10) / 180

    1 / C = 28 / 180

    C = 180 / 28 = 6.429 μ F
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