An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time?

Distance = (intial speed) X (Time) + 1/2 (acceleration) X (Time) [Third equation of motion]

As initial speed is zero, therefore;

Distance = 1/2 (acceleration) X (Time)

= 1/2 (6 X 15)

= 1/2 (90)

= 45 meters

Hence, the object traveled 45 meters.