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12 November, 23:57

dam is used to block the passage of a river and to generate electricity. Approximately 58.4 x 103 kg of water falls each second through a height of 20.1 m. If one half of the gravitational potential energy of the water were converted to electrical energy, how much power (in MW) would be generated

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  1. 13 November, 00:04
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    8.049 MW

    Explanation:

    The expression for gravitational potential energy is given as

    Ep = mgh ... Equation 1

    Ep = gravitational potential energy, m = mass of water, h = height, g = acceleration due to gravity.

    Given: m = 58.4*10³ kg, h = 20.1 m, g = 9.81 m/s²

    Substitute into equation 1

    Ep = 58.4*10³ (20.1) (9.81)

    Ep = 1.6098*10⁷ J.

    If one half the gravitational potential energy of the water were converted to electrical energy

    Electrical energy = Ep/2

    Electrical energy = (1.6098*10⁷) / 2

    Electrical energy = 8.049*10⁶ J

    In one seconds,

    The power generated = 8.049*10⁶ W

    Power generated = 8.049 MW
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