A small puck with a mass of 0.10 kilograms is sliding in the + x-direction on an air table with an initial speed of 8.0 meters/second. The puck collides with a larger puck that is initially at rest. The larger puck has a mass of 0.40 kilograms. After the collision, the smaller puck has a speed of 3.4 meters/second at an angle of + 60° from its original path. The angle made by the larger puck is - 35°. What is the x-momentum after the collision if the velocity of the larger puck after the collision is 1.5 meters/second?

0.8 kilogram meters/second

1.5 kilogram meters/second

2.1 kilogram meters/second

3.6 kilogram meters/second

4.8 kilogram meters/second

Question

Carley Pugh

Physics

21 August, 07:51

A small puck with a mass of 0.10 kilograms is sliding in the + x-direction on an air table with an initial speed of 8.0 meters/second. The puck collides with a larger puck that is initially at rest. The larger puck has a mass of 0.40 kilograms. After the collision, the smaller puck has a speed of 3.4 meters/second at an angle of + 60° from its original path. The angle made by the larger puck is - 35°. What is the x-momentum after the collision if the velocity of the larger puck after the collision is 1.5 meters/second?

0.8 kilogram meters/second

1.5 kilogram meters/second

2.1 kilogram meters/second

3.6 kilogram meters/second

4.8 kilogram meters/second

+5

Answers (1)

Know the Answer?

Bennett · Answer 1

By definition we have the momentum is:

p = m * v

Where

p: linear momentum

m: mass

v: speed.

For this case, momentum is conserved!

initial x momentum = 0.1kg * 8m / s = 0.8kg · m / s = final x-momentum

All the rest is clutter.

the answer is

0.8 kilogram meters/second