Ask Question
28 June, 09:38

The spring, initially at rest, was compressed by the blue box by 0.15 m. The spring constant of the spring is 300 N/m. The mass of the box was 0.2 kg. What is the max height of the box when it comes to rest on the ramp

+3
Answers (1)
  1. 28 June, 09:43
    0
    1.72m

    Explanation:

    Step 1:

    Data obtained from the question.

    Displacement (x) = 0.15 m

    Spring constant (K) = 300 N/m

    Mass (m) = 0.2 kg

    Height (h) = ?

    Step 2:

    Determination of the energy in the spring.

    The energy is a spring can be obtained by the following equation:

    E = 1/2 kx^2

    E = 1/2 x 300 x 0.15^2

    E = 150 x 0.0225

    E = 3.375J

    Step 3:

    Determination of the maximum height.

    At maximum height, the energy stored is the spring is equal to the potential energy i. e

    Energy stored in the string = potential energy

    E = P. E

    Recall:

    Potential energy = mgh

    Where:

    m is the mass = 0.2kg

    g is the acceleration due to gravity = 9.8m/s2

    h is the height. = ?

    Potential energy (P. E) = 3.375J

    PE = mgh

    3.375 = 0.2 x 9.8 x h

    Divide both side by 0.2 x 9.8

    h = 3.375 / (0.2 x 9.8)

    h = 1.72m

    Therefore, the maximum height of the box is 1.72m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The spring, initially at rest, was compressed by the blue box by 0.15 m. The spring constant of the spring is 300 N/m. The mass of the box ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers