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5 November, 16:51

On another planet, a morble is released from rest at the top of a high cliff. It falls 4.00 m in the first 1 s of its motion. Through what additional distance does it fall in the next 1 s?

(a) 4.00 m

(b) 8.00 m

(c) 12.0 m

(d) 16.0 m

(e) 20.0 m

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Answers (1)
  1. 5 November, 17:03
    0
    option c is correct

    additional distance is 12 m

    Explanation:

    given data

    height = 4 m

    time = 1 s

    to find out

    additional distance in next 1 s

    solution

    we will apply here formula for height

    height = 1/2 * g*t² ... 1

    put here value height = 4 and t = 1 s

    4 = 1/2 * g * (1) ²

    g = 8 m/s²

    and

    for time next 1 sec

    from equation 1

    height = 1/2 * g*t²

    put here t = 2 s so

    h2 - h1 = 1/2 * g * (2² - 1²)

    h2 - h1 = 1/2 * 8 * (2² - 1²)

    h2 - h1 = 4 (4-1)

    h2 - h1 = 12 m

    so option c is correct

    additional distance is 12 m
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