A clock moves past you at a speed of 0.9 c. How much time passes for you for each second that elapses on the moving clock?

0.436 s

1.15 s

2.29 s

infinity

The following formula t’ = t / sqrt (1-v²/c²) will be used to solved the given problem. The lorentz factor is the aspect by which time, length and relativistic mass alteration for an entity though that object is moving. The expression seems in numerous equations in distinct relativity and ascends in origins of the lorentz transformations.

Given the following:

t’ = the time from the perspective of the clockt = the timesqrt (1-v²/c²) = the lorentz factor

To solve:

t’ = t / sqrt (1 - (0.9c) ²/c²)

t’ = t / sqrt (1-0.81c²/c²)

t’ = t / sqrt (1-0.81)

t’ = t / sqrt 0.19

t’ = t / 0.436

t’ = 0.436 t’

t / t’’ = 0.436 second per every second intervened on the moving clock.