A howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 4.6 km. assume the acoustic output of a howler to be uniform in all directions and that the threshold of hearing is 1.0 * 10-12 w/m2. what is the acoustic power emitted by the howler?

The acoustic power of a specific sound is determine by multiplying the square of the distance and the threshold of hearing. We have to convert the distance first from kilometers to meters.

distance = (4.6 km) x (1000 meters / 1 km) = 4600 meters

Performing the required operation,

Acoustic power = (1.0 x 10^-12 W/m²) (4600 m) ²

Acoustic power = 2.116 x 10^-5 W

Thus, the acoustic power is approximately 2.12 x 10^-5 W.