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15 May, 09:56

A record turntable is rotating at 33 1 3 rev/min. a watermelon seed is on the turntable 5.0 cm from the axis of rotation. (a) calculate the acceleration of the seed, assuming that it does not slip. (enter the magnitude.)

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  1. 15 May, 10:02
    0
    Since the motion is rotational, we can associate this with centrifugal/centripetal acceleration. The formula for this is:

    a = v²/r = (rω) ²/r = rω²

    where ω is the angular velocity and r is the radius

    Let's convert v in terms of rad/min. The conversion from rev to rad is, 1 rev = 360° = 2π. So,

    ω = 33 1/3 rev/min * 2π rad/1 rev = 209.44 rad/min

    a = 5 cm (209.44 rad/min) ²

    a = 219,325.568 cm/min²
  2. 15 May, 10:19
    0
    Distance D = 5 cm = 0.05m

    Revolutions = 33.33 per min = > t = 60 sec

    Acceleration is v^2 / r, so first we need to find velocity

    Velocity = (D x 3.14 x r) / t = > (0.05 x 3.14 x 33.33) / 60

    Velocity = 0.0872 m/s

    Acceleration = v^2 / r = 0.0872^2 / 0.05 = 0.152.
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