A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much energy was delivered to the circuit?

Question

Ryker David

Physics

21 February, 04:56

A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much energy was delivered to the circuit?

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Answers (1)

Know the Answer?

Jon Bender · Answer 1

E = 0.18 J

Explanation:

given,

Potential of the battery, V = 9 V

Charge on the circuit, Q = 20 m C

= 20 x 10⁻³ C

energy delivered in the circuit

E = Q V

E = 20 x 10⁻³ x 9

E = 180 x 10⁻³

E = 0.18 J

Energy delivered in the circuit is equal to E = 0.18 J