2 cycleists, 90 miles apart starting riding toward each other at some times one cycles twice as fast as the other if they meet 2 hrs later at what average speed is each cyclist traveling

Average speed of the first car = 15 miles/hr

Average speed of the second car = 30 miles/hr

Explanations:

distance = d = 90 miles

Time = 2 hrs

let speed of first cyclist = v

speed of second cyclist = 2v

relative speed = v + 2v = 3v

using relative speed = Total distance/Total time

3v = 90/2

3 v=45

v=15 miles/hr

so speed of first cyclist = 15 miles/hr

speed of second cyclist = 2 (15) = 30 miles/hr