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3 December, 00:17

A ball is thrown directly downward with an initial speed of 8.00 m/s, from a height of 30.0m. After what time interval does it strike the ground?

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  1. 3 December, 00:26
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    The acceleration is - 9.8m/s^2. The initial velocity is - 8m/s. The initial position is 30m. This describes a position function of

    - (9.8/2) t^2-8t+30=0

    Solve the quadratic equation for t to get t=1.789s
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