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3 April, 04:29

If the kinetic energy possessed by a man of 50kg is 625J, the speed of man is

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  1. 3 April, 04:53
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    Answer: v = 5 m/s

    Explanation: Solution:

    KE = 1/2 mv²

    Derive to find v.

    v = √ 2KE / m

    Substitute the values

    v = √2x 625 J / 50 kg

    = √ 1250 J / 50 kg

    = √ 25 kg. m/s / kg

    = 5 m/s

    Unit for J can be expressed in kg. m/s so we cancel kg and the remaining unit is m/s.
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