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1 July, 13:35

The sound level produced by one singer is 70.8 dB. What would be the sound level produced by a chorus of 37 such singers (all singing at the same intensity at approximately the same distance as the original singer)

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  1. 1 July, 13:43
    0
    86.48 dB. Ans

    Explanation:

    Sound level by one singer = 70.8 dB

    = 7.08 B

    If I be its intensity in terms of watt/m²

    log (I / 10⁻¹²) = 7.08 (given)

    I / 10⁻¹² = 10⁷°⁰⁸

    I = 10⁻¹² x 10⁷°⁰⁸

    = 10⁻⁴°⁹²

    =.000012022 W / m²

    intensity by 37 singers

    = 37 x. 000012022 W / m²

    =.0004448378

    = 4448.378 x 10⁻⁷

    intensity level

    = log I / 10⁻¹² B

    = log 4448.378 x 10⁻⁷ / 10⁻¹²

    = log 444837800 B

    log 4448378 + 2 B

    = 6.6482 + 2 B

    8.6482 B

    intensity level = 8.6482 B

    = 86.48 dB. Ans
  2. 1 July, 13:46
    0
    86.48 dB

    Explanation:

    86.48 dB

    Explanation:

    sound level intensity, β = 70.8 dB

    Io = 10^-12 W/m²

    Let the intensity if I at the level of 70.8 dB

    Use the formula

    7.08 = log I + 12

    log I = - 4.92

    I = 1.2 x 10^-5 W/m²

    There are 37 singers, so the total intensity is I'.

    I' = 37 x I

    I' = 37 x 1.2 x 10^-5 = 4.45 x 10^-4 W/m²

    Let the sound intensity is β' in decibels.

    Use the formula

    β' = 86.48 dB
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