What is the pressure exerted by 0.801 mol of co2 in a 12 l container?

We assume that the gas is an ideal gas so we can use the relation PV=nRT. Assuming that the temperature of the system is at ambient temperature, T = 298 K. We can calculate as follows:

PV = nRT

P = nRT / V

P = (0.801 mol) (0.08205 L-atm / mol-K) (298.15 K) / 12 L

P = 1.633 atm