Two particles are separated by a certain distance. the force of gravitational interaction between them is f0. now the separation between the particles is tripled. find the new force of gravitational interaction f1.

as i recall, gravity is relative to the square of the distance.

so if the distance is tripled, then the gravitational attraction would be reduced by 3^2 or 1/9.

so F1 = F0/9

if the satellite is 2R from the center, and is moved to 4R (doubled would be 3R, tripled is 4R) then the distance is twice, and gravity would be 2^2 or 1/4.