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25 March, 16:44

The intensity of the sun's radiation incident upon the earth is about i=1.4kw/m2. suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. what is the total solar power p absorbed by the panels?

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  1. 25 March, 17:12
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    Intensity = power / Area

    ⇒ Power absorbed = 1 * A ⇒ 1.4 * 10∧3 * (10)

    = 14000 Watt = 14 kWatt

    time - averaged intensity divided by speed of light in free space is the radiation pressure

    P = (1.4 * 1000) / c

    Force = pressure * area ⇒ ((1.4 * 1000) / (10∧8)) * 10

    = 0.00004666666N

    0.000047N
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