A particle's velocity is described by the function vx=kt2m/s, where vx is in m/s, t is in s, and k is a constant.

The particle's position at t0=0s is x0 = - 8.10 m. At t1 = 2.00 s, the particle is at x1 = 8.00 m.

Determine the units of k in terms of m and s.

Question

4 February, 23:32

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Answers (1)

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Alayna Burnett · Answer 1

ms^ (-3)

Explanation:

V = kt^2

m/s = k (s) ^2

k = m / s^ (3)

k = ms^ (-3)

A particle's velocity is described by the function vx=kt2m/s, where vx is in m/s, t is in s, and k is a constant.The particle's position at t0=0s is x0 = - 8.10 m. At t1 = 2.00 s, the particle is at x1 = 8.00 m.Determine the units of k in terms of m and s.