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11 May, 21:55

A 1.50 kg rock whose density is 4700 kg/m3 is suspended by a string such that half of the rock's volume is under water.

What is the tension in the string? (In N)

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  1. 11 May, 22:01
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    Tension T = 13.14N

    Explanation:

    Given:

    Mass of rock m = 1.50kg

    Density of rock p = 4700kg/m^3

    Volume of rock V = mass/density = m/p

    V = 1.50kg/4700kg/m3 = 3.19*10^-4m3

    Taking the summation of forces acting on the rock;

    T-W+Fb = 0

    T = W - Fb ... 1

    T = tension

    W = weight of rock

    Fb = buoyant force

    Fb = pw (0.5V) g = density of water * Volume under water*™ acceleration due to gravity

    g = 9.8m/s^2

    T = mg - pw (0.5V) g

    T = 1.50*9.8 - 1000kg/m^3 * 0.5 (3.19 * 10^-4) * 9.8

    T = 13.14N
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